-5cos^2(x)+4cos(x)+1=0

Solution for -5cos^2(x)+4cos(x)+1=0 equation:

Simplifying
-5cos2(x) + 4cos(x) + 1 = 0

Multiply cos2 * x
-5cos2x + 4cos(x) + 1 = 0

Multiply cos * x
-5cos2x + 4cosx + 1 = 0

Reorder the terms:
1 + 4cosx + -5cos2x = 0

Solving
1 + 4cosx + -5cos2x = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 4cosx + -1 + -5cos2x = 0 + -1

Reorder the terms:
1 + -1 + 4cosx + -5cos2x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 4cosx + -5cos2x = 0 + -1
4cosx + -5cos2x = 0 + -1

Combine like terms: 0 + -1 = -1
4cosx + -5cos2x = -1

Reorder the terms:
1 + 4cosx + -5cos2x = -1 + 1

Combine like terms: -1 + 1 = 0
1 + 4cosx + -5cos2x = 0

The solution to this equation could not be determined.